For what values of x does the curve y^2x^3-15x^2=4 have horizontal tangent lines
Accepted Solution
A:
We have the following curve:
[tex]y^2x^3-15x^2=4[/tex]
To find the tangent lines to the curve
we need to use the concept of derivative, but we can’t solve this
problem for [tex]y[/tex], thus, let's apply implicit differentiation, so:
This is an absurd result because it is
impossible for a squared number to get a negative number. So the conclusion is that there is no any value of [tex]x[/tex] in
which the curve has horizontal tangent lines.